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A solution contains 29.1g per litre of aluminium Sulphate. Calculate the number of Sulphate ions in 350cm3 of the solution.(Al = 27, S = 32, O = 16) Avogadro’s constant = 6.0 x 1023.

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Molar mass of Al2(SO4)3 = 27 x 2 + (32 x 3) + (16 x 4 x 3) = 342
Moles of Al2(SO4)3 in 1000cm3 = 
Moles of Al2(SO4)3 in 350cm3 =
Al2(SO4)3(aq) →2Al3+(aq) + 3SO42-(aq)
1 mole of Al2(SO4)3 produce 3 moles of SO42- ions
0.02979 moles → 0.02979 x 3 moles of SO42- ions
Number of SO42- ions = 0.08937 x 6.0 x 1023 = 5.36 x 1022 ions.

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