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Determine the number of sodium ions contained in 25cm3 of 0.5M sodium carbonate solution [a=6.023 x 1023]  

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Moles of Na2CO3 =   25   × 0.5
                                1000
                           =0.0125
Na2CO3(aq) → 2Na+(aq) + CO2−3(aq) 
Moles of Na= 2 x 0.0125
                    = 0.025
Number of Na+ = 0.025 x 6.023 x 1023
                       = 1.5058 x 1022

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