INSTRUCTIONS TO CANDIDATES
- This paper consists of 12 questions.
- Answer ALL the questions in the spaces provided.
- ALL working MUST be clearly shown.
- ALL numerical answers MUST be expressed in decimal forms.
SECTION A (25 MARKS)
Answer all the questions in this section in the spaces provided.
- The Figure below shows part of a scale of vernier calipers. What is the reading indicted by the scale? (2 marks)
- The Figure shows two match sticks placed on water in a basin a few centimeters apart.
State and explain the observation made when a drop of soap solution is placed at a point marked x. (2 marks) - When a body of mass 0.35kg is acted upon by a force, its velocity changes from 3.5m/s to 6.0m/s.Determine the power developed by the force. (2marks)
- Figure below shows a uniform rod 4m long and of mass 2kg. It is pivoted 1m from one end and balanced horizontally by a string attached near the other end.
Determine the position where a mass of 5kg should be placed on the rod so that the rod remains horizontal and the tension in the string is zero. (3 marks) - Water flows steadily along a horizontal pipe at a volume rate of m3/s. if the area of cross-section of the pipe is 20cm2 . Calculate the velocity of the fluid. (2marks)
- State any two states of equilibrium. (2 marks)
- A ball is thrown from the top of a cliff 20m high with a horizontal velocity of 10ms-1 . Calculate the distance from the foot of the cliff to where the ball strikes the ground. (3 marks)
- Explain one advantage of mercury over alcohol as a thermometric liquid. (1mark)
- A body of mass M is allowed to slide down an inclined plane. State two factors that affect its final velocity at the bottom of the inclined plane. (2marks)
- For an enclosed system with a liquid, a force is applied at one point.
- Briefly explain how force is transmitted to other parts of the system. (1 marks)
- State one application of such a system. (1 marks)
- A 150g mass tied on a string is whirled in a vertical circle of radius 30cm with a uniform speed. At the lowest position the tension in the string is 9.5N, Calculate the velocity of the mass. (2 marks)
- A spring of elastic constant K has its length increased from 4.00m when unloaded to 4.25m when loaded with a 75N weight. Assuming that the elastic limit is not exceeded, determine the value of K. (2 marks)
SECTION B: 55 MARKS
-
- Sketch a block and tackle pulley system with three movable pulleys in the lower block and two fixed pulleys in the upper block. (2marks)
- Find:
- Velocity ratio (V.R.). (1mark)
- An effort of 450 N is used to raise a load of 2700N.Determine:
- Mechanical advantage (M.A) (2marks)
- Efficiency of the pulley system. (2marks)
- All the wasted energy is used to raise the lower block and to overcome frictional force between the pulleys and moving parts; determine the weight of the lower block if the frictional force is 3.6N. (2marks)
- If the load moved through a distance of 50cm, determine the useful work done by the effort. (2marks)
- John applied a force of 400N in pushing a stationery wall. If he took one hour to push the wall, calculate the power developed. (1mk)
-
- State two factors that affect the boiling point of a liquid (2 marks)
- 100g of a liquid at a temperature of 10°C is poured into a well lagged calorimeter. An electric heater rated 50W is used to heat the liquid. The graph in figure shows the variation of the temperature of the liquid with time.
- From the graph, determine the boiling point of the liquid (1 mark)
- Determine the heat given out the by the heater between the times t = 0.5 minutes and t = 5.0 minutes (2 marks)
- From the graph determine the temperature change between the times t = 0.5 minutes and t = 5.0 minutes, hence determine the specific heat capacity of the liquid. (3 marks)
- 1.8 g of vapor was collected from above the liquid between the times t= 3.5 minutes and t= 4.5 minutes. Determine the specific latent heat of vaporization of the liquid. (3 marks)
-
- Define “absolute zero temperature” for an ideal gas (1 mark)
- Using kinetic theory, explain Boyle’s law for an ideal gas. (2marks)
- The diagram shows an experiment to investigate the relationship between volume and temperature of a fixed mass of gas at constant pressure.
- Explain the function of;
- Concentrated sulphuric acid (1 mark)
- Stirrer (1 mark)
- Explain how the set up above can be used to verify Charles law for an ideal gas (3marks)
- On the grid below sketch a graph of volume (cm 3 ) against temperature ( 0 c). Mark with letter T the absolute zero temperature. (2 marks)
- Explain the function of;
- A column of air 20cm long is trapped by mercury thread 6cm long as shown in figure below.
If the tube is now inverted, determine column X in figure b).Take atmospheric pressure as 76cm of mercury. (2marks)
-
- State the law of floatation (1 mark)
- Figure below shows a simple hydrometer
- Identify the parts labelled A and B (2 marks)
- State the purpose of the part labelled B (1 mark)
- How would the hydrometer be made more sensitive? (1 mark)
- Describe how the hydrometer is calibrated to measure relative density. (3 marks)
- Figure shows a cork floating on water and held to the bottom of the beaker by a thin thread.
- Name the forces acting on the cork (2 marks)
- Describe how each of the forces mentioned in(i) above changes when water is added until the container is completely filled (2 marks)
- Name the forces acting on the cork (2 marks)
-
-
- What is meant by perfectly inelastic collision. (1 mark)
- A minibus of mass 1600kg travelling at a constant velocity of 20mls collides with a stationary car of mass 800kg. The impact takes 2seconds before the two moves together and come to rest after 15seconds. Determine.
- The common velocity. (3marks)
- The distance moved after the impact. (2 marks)
- The impulse force. (2 marks)
-
MARKING SCHEME
SECTION A
- Main scale reading = 3.20 cm
Vernier scale reading = 0.05 cm ✓1 for both readings
Reading on the scale = 3.25 cm. ✓1 -
- Match sticks moves away from each other ✓1
- Soap solution weakens surfaces tension in between hence stronger force on pulls them outwards ✓1
- Match sticks moves away from each other ✓1
- P=F∆V✓ =3.5×(6.0-3.5) = 8.75W✓
- f1d1 = f2d2
20 × 1.0 = d2 × 50
20/50 = 0.4m - Flow_ rate = A × speed
8 × 10−3 m3/s = 20 × v
10000
v = 8 × 10¯³ × 10000
20
v = 4m/s -
- Neutral
- Unstable
- h = ½gt2 = 20 = ½ × 10× t2 → t = 2 seconds; award for time
R = ut → R = 10 × 2; = 20m formula/sub and the correct answer with units - Higher boiling point so it can measure higher temperature than alcohol;
-
- Angle of inclination of the plane
- Vertical Height of the inclined plane
- Length of the plane
- Frictional force between the plane and the body
Maximum of two marks but consider only the first two responses of the learner
-
- Pressure is developed at the point of application of the force. ✓1Since the liquid is incompressible, pressure is uniformly transmitted and force is generated.✓1
- Hydraulic machines (brakes, press,lift)✓1
- F= mv² + mg ✓1
r
9.5 = 150 × v2 + 150 × 10 ✓1
1000 30/100 1000
V2 = 8.0 × 1000 × 30 =16
150 × 100
V=4.00m/s ✓1 - e = 4.25 − 4.00 = 0.25m
F = Ke
75 = 0.25k ✓1
K = 300N/m ✓1
SECTION B
-
-
-
- V.R =Number of the ropes supporting the load = 6
-
- M.A = L = 2400 = 5.333
E 450 - Efficiency of the pulley system.
M.A × 100% =
V.R
5.333 × 100% = 88.88%
6
- M.A = L = 2400 = 5.333
- Wasted effort = 11.12 × 450 = 50.04N
Wasted effort = Weight of lower block + Frictional Force
Weight of lower block = 50.04 − 3.6N = 46.44N
- Load = Load distance = 2400 × 0.5 = 1200J
- Power = work done = 400 × 0 = 0J
time 3600
-
-
-
- Impurities;
- Pressure;
-
- 800C ;
- time = (5 − 1.5) × 60 = 210 seconds;
heat(energy) = power × time = 50 × 210; = 10500J;
- Change in temperature = 80 − 20 = 60°C ;
Heat energy absorbed = mcΔθ → 10500 = 0.1 × c × 60 ;formula or substitution
c = 10500 = 1750J/kg K ; correct answer with units
0.1×60 - Heat energy supplied by the heater = heat energy spent to vaporize the liquid ;
mLv = 50 × 1 × 60; correct substitutions for both energy supplied and absorbed
Lv = 3000 = 30000J/kg; correct answer with correct units
0.1
-
-
- The temperature at which the volume/ pressure/K.E of a gas is assumed to be zero.✓1
- Reducing the volume increases the number of collisions of gas particles with the walls of the container per unit time.✓1Therefore the rate of change of momentum will also increase leading an increase in pressure.✓1
-
-
-
- Serves as a pointer to the volume on scale or
- To trap the gas in the tube or
- A drying agent for the gas✓1
- To make the temperature of the bath uniform✓1
-
- Heat the bath and record the temperature and height/volume of air trapped at suitable temperature interval.✓1 Plot a graph of volume/height against temperature.✓1 The graph is a straight line indicating proportional change in volume and temperature✓1
- See sketch on grid.
-
- P1V1=P2V2
(76 + 6 )(20) = (76 − 6)x ✓1
X = 82 × 20 = 23.429cm ✓1
70
-
- A floating body displaces its own weight of fluid in which it floats;
-
-
- A bulb ;
- B lead-shots ;
- It enables the hydrometer float upright ;
-
- Using a narrower glass-stem ;
-
- Float the hydrometer in a liquid of known relative density and mark level of the liquid on the stem;
- Float the hydrometer again in another liquid of known relative density and mark its level on the stem;
- Divide the length between the marks into equal divisions and label it accordingly ;
-
-
- Tension;
- Up-thrust;
- Weight;
-
- Tension increases;
- Up-thrust increases;
- weight remains constant
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-
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- collision where only linear Momentum is conserved and bodies moves together after collision (coelesce).
-
- Momentum before collision = Momentum after collision
(1600 x 20) + (800 x 0) = (1600 + 800)V
V = 32000 = 13.33m/s
2400 - V = U + at
⇒ 13.33 + 15a ⇒ pa = −0.89m/s²
V² = U² + 2as ⇒ S = V² − U² = 0 − (13.33)²
2a −2(0.89)
= 99.83m
- Momentum before collision = Momentum after collision
- Impulse tone = ΔP = 1600(20 − 13.33) for minibus
2
= 5336N
Or 800(13.33 − 0) for a car
2
= 5336N.
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