CHEMISTRY
PAPER 3:PRACTICAL
INSTRUCTIONS
- Write your name and index number in the spaces provided above.
- Sign and write the data of the examination.
- Answer all the questions in the spaces provided.
- You are not supposed to start working with the apparatus for the first 15 minutes of 2¼ hours allowed for this paper. This time is meant to read through the paper and ensure you have all the chemicals and apparatus require.
- All working must be clearly shown
- KNEC mathematical tables and silent electronic calculations may be used.
- All questions should be answered in English
QUESTION 1
You are provided with:
- Solid A 5.0g (COOH)2·H2O
- Solution B 0.13M KMnO4
Task
- You are supposed to determine the solubility of A at different temperatures.
- Determine the number of moles of water of crystallization in solid A.
PROCEDURE 1
- Using a burette, add 4cm3 of distilled water to solid A in a boiling tube.
- Head the mixture while stirring with the thermometer to about 800C.
- When the whole solid dissolves, allow the solution to cool while stirring with the thermometer
- Note the temperature at which crystals first appear and record this temperature in the table 1 below.
- Using a burrete add 2cm3 more into the content of the boiling tube and warm until the solid dissolve.
- Remove from the flame and allow the solution to cool in air while stirring.
- Record the temperature at which crystal first appear in table 1.
- Repeat procedure (b) 3 more times and complete table 1 below.
- Retain the content of the boiling tube for procedure II
Table 1
Volume of water in the boiling tube (cm3) | Temperature at which crystals of solid A appear (0C) | Solubility of solid A g/100g of water |
4 6 8 10 12 |
-
- Draw a graph of solubility of solid A (vertical axis) against temperature (3mks)
- From your graph determine the solubility of solid A at 600C (1mk)
PROCEDURE II-
- Transfer the contents of the boiling tube into a 250ml volumetric flask.
- Add distilled water up to the mark
- Label this solution A
-
- Using a clean pipette and a pipette filler, transfer 25ml of solution A into a conical flask.
- Warm the mixture up to 60ºC
- Fill a burette with solution B
- Titrate B against the hot solution A until a permanent pink colour persist
- Read your results in Table 2 below
- Repeat (b) 2 more times are record your results in the table 2 below.
Table 2I II III FINAL BURETTE READING INITIAL BURETTE READING VOLUME OF SOLUTION B USED (CM3)
-
-
- Calculate the average volume of solution B used (1mk)
- Calculate the number of moles of B used (1mk)
- Given 2 moles of KmNO4 react with 5 moles of A, calculate the number of moles of A in 25cm3 (1mk)
- Calculate the molarity of A (1mk)
- Determine the molar mass of A (1mk)
- Determine the value of X (1mk)
(C=12, O=16 H=1)
QUESTION 2
You are provided with solid C. Use it to carry the test below. Dissolve the whole of C into 10cm3 of water and divide it into five portions.
- To the 1st portion add sodium sulphate solution.
Observations Inferences
(1mk)
(1½mk) - To the 2nd portion add Ammonia solution dropwise until in Excess.
Observations Inferences
(1mk)
(1mk) - To the 3rd portion add sodium Hydroxide dropwise until in Excess.
Observations Inferences
(1mk)
(1mk) - To the forth portion add Lead (II) Nitrate solution
Observations Inferences
(½mk)
(2mk) - To the last portion add Barium Nitrate solution
Observations Inferences
(1mk)
(1mk)
QUESTION 3
You are provided with liquid D use it to carry the test below. Divide liquid D into four equal portions
- To the 1st portion add sodium hydrogen carbonate
Observations Inferences
(1mk)
(1mk) - To the 2nd portion add acidified potassium manganite (VII) (KmNO4)
Observations Inferences
(1mk)
(1mk) - To the 3rd portion add Bromine water
Observations Inferences
(1mk)
(1mk) - To the last portion add potassium dichromate(VI) and warm.
Observations Inferences
(1mk)
(1mk)
CONFIDENTIAL
In addition to the equipment and fittings found in a chemistry laboratory. Each candidate should be provided with;
- Solid A 5.0g measured accurately
- About 80cm3 of solution B
- About 0.5g solid C
- About 10cm3 of liquid D
- A thermometer (-10-110ºC)
- A burette
- A complete retort stand
- A pipette and a pipette filler
- 2 conical flasks
- A 250ml volumetric flask
- One boiling tube
- Five (5) test tubes
- 0.5g sodium hydrogen carbonate
- Two labels
ACCESS TO:
- Means of heating (Tripond stand and wire gauze)
- Sodium sulphate solution (NaSO4)
- Ammonia solution 2m
- 2m Sodium Hydroxide
- Lead Nitrate solution
- Barium Nitrate solution
- Acidified potassium manganite (VII) solution
- Bromine water
- Acidified potassium dichromate(VI) solution
NB:
- Solid A is 5.0g of oxalic acid (COOH)2 2H2O
- Solution B is KmnNO4
- Solid C is magnesium chloride MgCl2
- Liquid D is absolute ethanol
Preparations
- Solution B is made by dissolving 20g of solid KmNO4 in 200cm3 of 2.0m H2SO4 and toping to 1000cm3 by distilled water.
- Sodium Hydroxide is prepared by dissolving 80g of NaOH pellets in 600cm3 of distilled water and top to 1000cm3 with distilled water.
- Ammonia solution is prepared by dissolving 150ml of conc ammonia to 600cm3 of distilled water then top to the mark.
- Barium Nitrate is prepared by dissolving 26g of solid Barium Nitrate in 600cm3 of water then topping to 1000cm3 with distilled water.
- Lead nitrate is prepared by dissolving 30g of solid Lead Nitrate in 600cm3 of water then topping to 1000cm3 with distilled water.
- Sodium Sulphate is prepared by dissolving 14.2g of solid sodium sulphate in 600cm3 of distilled water then topping up to 1000cm3 with distilled water.
- Acidified Kmno4 is prepared by dissolving 3.2g of solid Kmno4 in 200cm3 of 2.0m H2SO4 acid then topping with distilled water to 1000cm3.
- Acidified K2Cr2O7 is prepared by dissolving 25g of solid K2Cr2O7 in 200cm3 of 2.0m H2SO4 then topping to 1000cm3 with distilled water.
MARKING SCHEME
QUESTION1
TABLE 1
Volume of water in the boiling tube (cm3) | Temperature at which crystals of solid A appear (0C) | Solubility of solid A g/100g of water |
4 | 70.0 | 125.0 |
6 | 59.0 | 83.3 |
8 | 54.0 | 62.5 |
10 | 47.0 | 50.0 |
12 | 40.0 | 41.7 |
AWARD a total of 7 MKS Distributed as follows.
- Complete table – 4mks
Condition and penalties- A table with 8-10 values award 4
- A table with 6-7 values a ward 3
- A table with 4- 5 values award 2
- A table with 2-3 values award 1
- A table with 1 value award ½
- A table with no value a ward 0
Penalties- Penalize ½ mk for each wrong value of solubility
- Penalize ½ one for unrealistic temperature readings ½ above 90ºC and below 10ºC
- DECIMALS TIED TO TEMPARATURE -1Mk
Accept;- Whole numbers
- 1 decimal place where the decimal should be 0 or 5 i.e 70.0 or 70.5
- Accept 2 decimal places where it should be .00, .25,.50 or .75
NB: If no consistence penalize fully.
- TREND – Tied to temperature i.e it should be decreasing (1mk)
- Accuracy – tied to temperature when 4cm3 of water was added
Accept 20C of the school value. - GRAPH – award a total of 3mks distributed as follows.
- Labeling (½mks)
- Both axis should be labeled if one is not or wronglylabeled award O
- Ignore units but if indicated they should be right otherwise penalize fully
- Scale – (½mks)
- The actual plotting should be halfof the page
- Peralize fully if scale changes on the way both axis must be correct.
- Plots (1mk)
- 4-5 correct plots award (1mk)
- 3 correct plots award (½mks)
- Less than 3 correct plots award 0
- Line – a smooth curve passing through 3 or more correct plots award 1mk
- Otherwise award 0
-
- award ½ mk for sloping or the graph
- award ½ mk for calculating
NB:- Award fully for calculation from correct graph even if not shown on the graph
- Reject any value from a wrong graph.
- Labeling (½mks)
TABLE 2
I | II | III | |
FINAL BURETTE READING | 12.5 | 12.5 | 12.5 |
INITIAL BURETTE READING | 0.0 | 0.0 | 0.0 |
VOLUME OF SOLUTION B USED (CM3) | 12.5 | 12.5 | 12.5 |
Award a total of 5mks distributed as follows
- Complete table (1mk)
- Complete table with 3 titration 1mk
- Incomplete table with 2 titrations ½ mk
- Incomplete table with 1 titration 0 mks
Penalties- Wrong arithmetic
- Invented table
- Unrealistic values i.e burette reading with more than 50cm3 and less than 1cm3 withoutexplanation.
- Unrealistic titre values
NB: penalize ½ once
- Use of decimals (1mk) (Tied to the 1st and 2nd row only)
Accept 1 or 2 decimal places used consistently otherwise penalize fully- If 2 dp are used the 2nd should be a “O” OR “5” e.g 20.10 or 20.15 otherwise penalize fully
- Accept the use of Zero as the initial burette reading i.e 0,0.0 or 0.0
- Accuracy (1mk)
- Complete the candidate value with the school value (S.V)
- If within 0.1 of the school value award 1mk
- If within 0.2 of S.V ward ½mk otherwise award 0
NB: Tick the candidate value that deserves a credit
- Complete the candidate value with the school value (S.V)
- PRINCIPLE OF AVERAGING ------------------------1MK
Conditions- If 3 titration done but only two are consistence and averaged award 1mk
- If 3 titration are done and consistency and averaged award 1mk
- If two titration are done and are consistency and averaged award 1mk
- If three consistency titration one done but 2 are averaged award 0
- If three 3 titration are done and are inconsistence and are done averaged award zero
- If two titration are done and are inconsistence and are averaged award 0
PENALTIES
- Penalize ½ for wrong arithmetic
- penalize ½mk if no working is shown and answer is correct
- penalize fully if no working is shown and answer given is wrong
- Accept rounding off or truncation to the 2nd d.p
e.g 12.666 12.67
or
12.66 12.66
NB:- The working of average must be marked before the mark for averaging is award in table 2.
- Accept the average volume if it work out exactly to a whole number.
- FINAL ACCURACY ----------------------(1MK) Tiled to correct average time.
Compare the candidate average time to the school value.- If within0.1 award 1mks
- If with n 0.2 award ½ mk
- Otherwise award 0
NB:- If there are 2 possible correct average titre, use the one the one close to the school value and award accordingly.
- If wrong value are averaged, pick the correct values average for the candidate and award accordingly.
- Record the marks as follows besides the table to the right.
CT – 1mk
D - 1mk
A -1mk
PA -1mk
FA - 1mk
Total 05 mks
- Calculate the number of moles of B used
1000 - 0.13
12.5 ?
= 12.5×0.131000 √ ½
0.001625 moles √ ½
= 0.0040625 √ ½ - Ans b×52
= 0.0040625 √ ½ - Ans c×100025 √ ½
= 0.1626m √ ½ - 5g 250cm3
20g – 1000
1×200.1625
= 123.07 √ ½ - 90 + 18x =123
18x = 33
x= 3318
x= 1.83
= 2
QUESTION 2
- To the 1st portion add sodium sulphate solution.
Observations Inferences No white precipitate formed (1mk)
Ba2+ Ca2+ and Pb2+ Absent
Each ½ mks
Penalize ½mk to a maximum of 1 ½ mks for any contradictory ion - To the 2nd portion add Ammonia solution dropwise until in Excess.
Observations Inferences No white precipitate insoluble in excess
NB: White precipitate ½ mk
Insoluble in excess ½ mkZn2+ absent (1mk)
Penalize 1mk for each contradicting ion to a maximum of (1mk) - To the 3rd portion add sodium Hydroxide dropwise until in Excess.
Observations Inferences A white precipitate ½
Insoluble in excess ½
Mg2+ present (1mk)
Accept Al3+ absent for ½mk
Panelize 1mks for any contracting ion to a Maximum of 1mks - To the forth portion add Lead (II) Nitrate solution
Observations Inferences A white precipitate is formed ½ mks
Cl-, So32- , SO4 2- and CO32- present
– ½ mk each
Penalize ½mk for any contradictory ion to a maximum of - To the last portion add Barium Nitrate solution
Observations Inferences No white precipitate formed
CI- Present (1mks)
-accept SO42- AND SO32- OR CO32- absent for fully marks
penalize 1mks for any contradictory ion to a maximum of 1mks
Three anions given – 1mk
Two anions given -½mk
One onion given – 0mk
QUESTION 3
- To the 1st portion add sodium hydrogen carbonate
Observations Inferences No fizzing/bubbling /hissing (1mk)
Reject
-fissiling
-SizzlingR- CooH Absent (1mk)
NB: Ignore H3O+ & H+ - To the 2nd portion add acidified potassium manganite (VII) (KmNO4)
Observations Inferences KMNO4 get decolorized
Or
KMNO4 turns from purple to colorless (1mk)
Reject
The solution turns colourless
It turns colourlessC= C OR –C= C- (½mk)
PresentR- OH Present (½mks)
NB: Penalize ½mk for any contradictory group to a maximum of
- To the 3rd portion add Bromine water
Observations Inferences Yellow /orange bromine water does not get decolonized
Accept
It remains yellow or orange
or –C C-
Absent
Penalize 1mk for any contradictory group to a maximum of - To the last portion add potassium dichromate(VI) and warm.
Observations Inferences K2CrO7 turns from orange to green R-OH Present (1mk)
Penalize 1mk for any contradictory group to a maximum of
Download Chemistry Paper 3 Questions and Answers with Confidential - Kapsabet Pre Mock Exams 2021/2022.
Tap Here to Download for 50/-
Get on WhatsApp for 50/-
Why download?
- ✔ To read offline at any time.
- ✔ To Print at your convenience
- ✔ Share Easily with Friends / Students
Join our whatsapp group for latest updates