## PHYSICS Marking Scheme - Form 1 End of Term 1 2019 Examinations

1.
1. 4.8 cm
2. to eliminate error because of the thickness of the ruler
1. Upthrust 3−2 = 1N
2. Air is compressible
3.
1. force applied
area of contact
2. By use of ball bearings
Lubrication by use of oils
Rollers
3. Enables one to walk
Enables the car to stop when breaks are applied
Lighting fire matchstick lights because of its friction with the rough surface
1. A=πr2
= 3.142 x (2/200)2
= 3.142 x 10-4 m2
2. p = hpg
= 2.8 x 0.8 x 1000 x 10
= 2.24 x 104 pa
3. F = P x A
= 2.24 x 104 x 3.142 x 10-4
= 7.0381N
1.
 Mass Weight Constant Varies from place to place SI unit is kg SI unit is N Scalar quantity Vector quantity Quantity of matter for a substance Force of gravity on a body
2.
1.
1. Put of the main switch before treating the shock
2. Run cold water over the affected part as you seek for further treatment (1mk)
• Physics teacher
• Engineer
• Architect
• Pharmacist
• surveyor
2.
1. In making modern weapons e.g laser guided bombs, missives
2. X- rays, body scanners and lasers are used in diagnosis and treatment of diseases
3. Modern farming methods e.g. use of green houses (2mks)

3.
1. A vector is a quantity that has direction as well as magnitude while scalar has magnitude only

1. 4. Soap dissolves in water and lowers the surface tension at that end of the stick. The surface tension on the other end which is now greater pulls the stick and makes it move in that direction. (2mks
5.
1. Mass of the paint = 7 -0.5 = 6.5 kg = 6500g
Volume = 5000cm 3
Pa = m/v=6500g/5000cm3= 1.3 gcm3
2. Mass of metal = 0.5 kg = 500g
P metal = 7800 kgm-3 = 7.8 g/cm3
V =m/p = 599g/7.8g/cm3=64.10 cm3
6.
• Surface tension
• Weight of the drop
7.
1. Mass – kilogram
2. Electric current – Ampere
3. Length – meter
4. Luminous intensity – candela
5. Thermodynamic temperature – Kelvin
1. 3.65 cm =3.65/100m
= 0.0365 m or 3.65 x 10-2
1. A=πr2
= 3.142 x [(0.1)2cm2]/4
= 3.142 x [0.01cm2]/4
= 0.00786 cm2
1.
1. Volume of water added = 0.25 cm3 x 20 = 5 cm3
2. New level of burette
= Orignal level – volume added
= 25 cm 3 – 5 cm3
= 20 cm3
2.
1. 1 mg = 0.000001kg
50mg = 50 x 0.000001 kg
= 0.00005 kg
2. 0.02 tonnes = 0.02 x 1000 kg
= 20 kg
3. 620 = 620 x 1000 = 620000mg (2mks)
1.
1. Pressure is force per unit area S.I unit is N/M2 or pascals (2mks)
2.
1. Incompressible
Low freezing point
High boiling point
Should not corrode the parts of the brake system
2. PA = PB
F1/A1=F2/A2
100/15=F2/50
F2=33.3 N
3. PA = PB
Pressure in liquids is transmitted equally in all directions
3. Density of mixture = mass of mixture/volume of mixture
mass of fresh water = 1800 x 1 = 1800g
mass of sea water = 2200 x 1.025 = 2255g
Density of mixture = 2255 x1800/1800+2200
= 1.01375 g/cm3

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