PHYSICS Marking Scheme - Form 1 End of Term 1 2019 Examinations

Share via Whatsapp
  1.  
    1. 4.8 cm
    2. to eliminate error because of the thickness of the ruler
  1. Upthrust 3−2 = 1N
  2. Air is compressible
  3.  
    1. force applied
      area of contact
    2. By use of ball bearings
      Lubrication by use of oils
      Rollers
    3. Enables one to walk
      Enables the car to stop when breaks are applied
      Lighting fire matchstick lights because of its friction with the rough surface
    1. A=πr2
      = 3.142 x (2/200)2
      = 3.142 x 10-4 m2
    2. p = hpg
      = 2.8 x 0.8 x 1000 x 10
      = 2.24 x 104 pa
    3. F = P x A
      = 2.24 x 104 x 3.142 x 10-4
      = 7.0381N
  1.  
     Mass  Weight 
     Constant  Varies from place to place
     SI unit is kg  SI unit is N
     Scalar quantity  Vector quantity
     Quantity of matter for a substance   Force of gravity on a body
  2.  
    1.  
      1. Put of the main switch before treating the shock
      2. Run cold water over the affected part as you seek for further treatment (1mk)
      • Physics teacher
      • Engineer
      • Architect
      • Pharmacist
      • surveyor
    2.  
      1. In making modern weapons e.g laser guided bombs, missives
      2. X- rays, body scanners and lasers are used in diagnosis and treatment of diseases
      3. Modern farming methods e.g. use of green houses (2mks)

  3.  
    1. A vector is a quantity that has direction as well as magnitude while scalar has magnitude only

      1. vector
  4. Soap dissolves in water and lowers the surface tension at that end of the stick. The surface tension on the other end which is now greater pulls the stick and makes it move in that direction. (2mks
  5.  
    1. Mass of the paint = 7 -0.5 = 6.5 kg = 6500g
      Volume = 5000cm 3
      Pa = m/v=6500g/5000cm3= 1.3 gcm3
    2. Mass of metal = 0.5 kg = 500g
      P metal = 7800 kgm-3 = 7.8 g/cm3
      V =m/p = 599g/7.8g/cm3=64.10 cm3
  6.  
    • Surface tension
    • Weight of the drop
    • Adhesion and cohesion
  7.  
    1. Mass – kilogram
    2. Electric current – Ampere
    3. Length – meter
    4. Luminous intensity – candela
    5. Thermodynamic temperature – Kelvin
  1. 3.65 cm =3.65/100m
    = 0.0365 m or 3.65 x 10-2
  1. A=πr2
    = 3.142 x [(0.1)2cm2]/4
    = 3.142 x [0.01cm2]/4
    = 0.00786 cm2          
  1.  
    1. Volume of water added = 0.25 cm3 x 20 = 5 cm3                                        
    2. New level of burette
      = Orignal level – volume added
      = 25 cm 3 – 5 cm3
      = 20 cm3
  2.  
    1. 1 mg = 0.000001kg
      50mg = 50 x 0.000001 kg
      = 0.00005 kg
    2. 0.02 tonnes = 0.02 x 1000 kg
      = 20 kg
    3. 620 = 620 x 1000 = 620000mg (2mks)
  1.  
    1. Pressure is force per unit area S.I unit is N/M2 or pascals (2mks)
    2.  
      1. Incompressible
        Low freezing point
        High boiling point
        Should not corrode the parts of the brake system
      2. PA = PB
        F1/A1=F2/A2
        100/15=F2/50
        F2=33.3 N
      3. PA = PB
        Pressure in liquids is transmitted equally in all directions
    3. Density of mixture = mass of mixture/volume of mixture
      mass of fresh water = 1800 x 1 = 1800g
      mass of sea water = 2200 x 1.025 = 2255g               
      Density of mixture = 2255 x1800/1800+2200 
      = 1.01375 g/cm3

Download PHYSICS Marking Scheme - Form 1 End of Term 1 2019 Examinations.


Tap Here to Download for 50/-




Why download?

  • ✔ To read offline at any time.
  • ✔ To Print at your convenience
  • ✔ Share Easily with Friends / Students


Join our whatsapp group for latest updates
Get on WhatsApp Download as PDF
.
Subscribe now

access all the content at an affordable rate
or
Buy any individual paper or notes as a pdf via MPESA
and get it sent to you via WhatsApp

 

What does our community say about us?

Join our community on:

  • easyelimu app
  • Telegram
  • facebook page
  • twitter page
  • Pinterest