- This paper consists of two sections A and B.
- Answer all the questions in the spaces provided.
- All workings must be clearly shown.
- Mathematical tables and silent electronic calculators may be used.
Section A ( 25 marks)
Answer all the questions in the spaces provided
- Figure 1 (a) below is micrometer screw gauge when closed, and figure 1 (b) shows the same micrometer screw gauge measuring the thickness of a sim card.
Determine the thickness of the sim card. (2mks) - A rectangular container measures 2.4cm x 4cm x 6cm. what is the weight of the mercury that will fill the container to the brim.
( take g =10N/kg, density of mercury =13600kg/m3) (3mks) - It is painful when you press a small piece of stone with your palm of the hand than when you place the same stone on the palm. Briefly explain. (2mks )
- Why are luggage compartments in buses placed under the seats rather than on the roof racks ( 1mks)
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- A uniform metre rule in balanced horizontally at its centre. When a mass of 50g is suspended at 4cm mark the rule balances horizontally if a mass M is suspended At 73cm mark. determine the mass m. (2 marks)
- Give one application of moment of force. 1mk)
- Figure below shows a U-tube containing coloured water, two boiling tubes Y and Z both painted black. A container with hot water painted black on one side and polished shinny on the opposite side is placed as shown in the diagram below.
- State the observation made after some time in the level of the liquid in the U-tube. (1mk)
- Explain your observation.(3mks)
- A stone is thrown vertically upwards from the edge of a platform. Eventually the stone lands without bouncing on the ground below the platform. Taking upwards velocity to be positive sketch the velocity –time graph of the motion of the stone. (2mks)
- Trees along a busy road grow bending towards the road, Explain. (1 mk)
- A solid displaces 5.5cm3 of ethanol when floating and 20.0cm3 when fully immersed in it. Given that the density of ethanol is 0.8g/cm. Calculate the density of the solid. ( 3 mks)
- A student observed light rays penetrating through a small hole on the roof of smoky room. State the observation made on the smoke particles. ( 1 mk)
- Give the energy transformation involved when a boy kicks a football to a wall. (1mk)
- Identify the forces acting on a ball bearing as it moves down a cylinder containing glycerine (2 mks)
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- State the law of conservation of energy. (1mks)
- It is easier to use a thick screw driver than a thin one. Explain. (1mk)
- The figure below shows a force-distance graph for a car being towed on a horizontal ground.
From the graph;- Calculate the total work done. ( 4 mks)
- If the velocity just before reaching point D is 0.6m/s. Calculate the power developed by the source providing the force at this point. ( 2 mks)
- An electric pump can raise water from a low level reservoir to a higher level reservoir at a rate of 3.6x10kg/hr. The vertical height the water is raised is 400m. if the rate of energy loss inform of heat is 200kw,determine the efficiency of the pump. (3.mks)
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- State two ways in which the centripetal force on a body of mass m can be increased. (2mks)
- Figure below shows an object at the end of a light spring balance connected to a peg using a string. The object is moving in a circular path on a smooth horizontal table with a constant speed.
- State what provides the centripetal force (1mk)
- Indicate with an arrow on the figure the direction of the centripetal force ( 1mk)
- State with a reason why the object is accelerating while its speed remains constant. (1mk)
- Given that the mass of the object is 0.5kg and it is moving at a speed of 8m/s at a radius of 2m ,determine the reading on the spring balance (3mks)
- A stone thrown vertically upwards reaches a height of 100m. determine:
- Initial velocity of the stone. ( neglect air resistance and take g= 10m/s) (3mks)
- Total time the stone is in air (2mks)
- Draw a block and tackles pulley system that has a velocity ration of 3. (2 mks)
Determine:- The mechanical advantage of the system in 80% efficient ( 3marks)
- The effort used, if the load lifted is 4.8N (3mks)
- The work done by the effort in lifting the load through a distance of 70cm (3marks)
- How much energy is wasted? (2 marks)
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- Define the term specific heat capacity. (1mk)
- The following data was obtained from an experiment to determine specific heat capacity of a solid by electrical method.
Mass of the solid. ………….750g
Initial temperature of solid……………..200C
Ammeter reading………….1.0A
Voltmeter reading…………6.0V
Final temperature of the solid…….240C
Time for which current flows in water……..6 minutes.- Draw a simple diagram to show how the experiment was done. (3mks)
- From the data given calculate;
- Electrical energy supplied to water. (2mks)
- Specific heat capacity of the solid. (3mks)
- The heat capacity of kerosene is 84JK-1. Calculate the quantity of heat energy required to warm kerosene from 20°C to 26° (3mks)
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- State Newton’s first law of motion (1 mk)
- A wooden block resting on a horizontal bench is given an initial velocity u so that it slides on the bench surface for a distance d, before coming to a stop. The values of d were measured and recorded for various values of initial velocity. Figure below shows the graph of u2 against d.
- Determine the slope of the graph. ( 2mks)
- Given that u2= 20kd, where k is a constant for the bench surface, determine the value of k form the graph. (2mks)
- A car of mass 800kg start from rest and accelerates at0.12m/s2 determine its momentum after it has moved 400m from the starting point ( 3 mks)
MARKING SCHEME
- Error 0.47mm
Thickness = 1.30mm − 0.47mm
=0.83mm - W = Mg
=P x V x G
=13600 x (2.4x4x6) x 10- x10
= 7.834N - When pressed, pressure increases or is high thus pain , when the stone is placed without pressing, pressure I slow thus less pain.
- To lower the position of 60g of the bus thus increasing stability
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- 50 x 46 = m x 23
M = 50 x 46
23
M = 100g -
- Opening and closing door
- Steering wheels
- Water taps
- Bicycle handle bars
- Sprinklers
- Spanners
- 50 x 46 = m x 23
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- Level of water decreases in limb B and rises in Limb A
- air in Z is heated faster than in Y. this is because dull surfaces are good better emitters of radiant heat. Expanded air pushes the level of water in lim B downwards raising the level in limb A
- Fast moving vehicles , increase the velocity of air between the vehicle and trees, this reduces pressure in between. Excess outside pressure pushes the trees towards the road making them bend.
- Mass of solid = 5.5 x 0.8
=4.4g
Volume of solid = 20cm3
Density of solid = 4.4
20
= 0.22g/cm3 - Smoke particles were seen to move in random motion ( brownian motion)
- Chemical energy – kinetic energy – sound and heat energy
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- Up thrust force
- Weight
- Viscous drag
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- Energy can neither be created nor destroyed but can only be changed from one form to another.
- a thick screw driver has a greater turning effect than a thin one.
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- total work done = area under the graph
= (200x20) + (600x20) + (1/2 x 10x 400) + (1/2 x (20+10) x 400)
= 4000+12000+2000+6000
= 24000J - Power = force x velocity
= 600 x 0.6
=360W
- total work done = area under the graph
- efficiency = 3.6x10x 400
(3.6 x 10x400) +200000
= 99.86%
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- Increasing the radius of the circular path
- Increasing the angular velocity
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- Tension in the string
- Shown/ indicated in the diagram( towards the Centre of the circular path).
- M = 0.5 kg F = MV2
V = 8 m/s r
R = 2 m = 0.5 x 8
2
F = 16N - Reading of the balance = tension m the string = centripetal force = 16N
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- U= √2gh
=√2 × 10 × 100
U = 44.72m/s - V= u − gt
0 = 44.72 − 10t
T = 2t
=2 x 4.472
T= 8.944(s)
- U= √2gh
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- M.A = V.R x 80/100
M.a = 3x80/100
M.a = 2.4 - M.A = L/E
2.4 = 4.8/E
E= 2N - Work done by effort = effort x distance
- = 2 x 70x3 =4.2J
100
Wasted energy = 4.2 – ( 4.8X70/100)
= 4.2J – 3.36j
= 0.84J
- M.A = V.R x 80/100
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- Heat capacity is heat energy required to change the temperature of a substance by 1 Kelvin
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- E = vIt
=6x1x(6x60)
=2160Joules - MCO = VIt
C = VIt/MO =2160/0.75x(24-20)
= 2160/0.75x4
= 720Jkg-1K-1 (c)
- E = vIt
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- Q. = CO
=8X(26-20)
=504Joules
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- A body remains in its state of rest or uniform motion in a straight line unless acted upon by an external force.
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- Slope = change in Y
change in x
= 100
16.25
= 6.154m/s2 - 20K = gradient
K = 6.154
20
K = 0.307 m/s2 - M = 800KG
U = 0M/s
a= 0.12M/S2
S=D = 400M
V = 4+29 s
V = 0+2x 0.12 x 400
V = 960m/s
Momentum = mass x velocity
= 800 x 96
= 76800kg m/s
- Slope = change in Y
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